This program helps you to find the number of even and odd numbers present in the given array

#include<stdio.h>
int main(){
int odd=0,even=0,i;
int numbers[10] = {7,10,4,13,8,5,10,25,88,14}; //Change the numbers here
for(i=0; i < 10 ;i++){
if( numbers[i] %2 == 0){
++even;
}else{
++odd;
}
}
printf("There are %d even numbers in the give array",even);
printf("\nThere are %d odd numbers in the give array",odd);
return 0;
}

## Output :

There are 6 even numbers in the give array
There are 4 odd numbers in the give array

## Comments :