This program helps you to find the number of even and odd numbers present in the given array

#include<iostream>
using namespace std;
int main(){
int odd=0,even=0;
int numbers[10] = {7,10,4,13,8,5,10,25,88,14}; //Change the numbers here
for(int i=0; i < 10 ;i++){
if( numbers[i] %2 == 0){
++even;
}else{
++odd;
}
}
cout<<"\nThere are " <<even<<" even numbers in the give array";
cout<<"\nThere are " <<odd<< " odd numbers in the give array";
return 0;
}

## Output :

There are 6 even numbers in the give array
There are 4 odd numbers in the give array

## Comments :