This program helps you to find the number of even and odd numbers present in the given array
#include<iostream> using namespace std; int main(){ int odd=0,even=0; int numbers[10] = {7,10,4,13,8,5,10,25,88,14}; //Change the numbers here for(int i=0; i < 10 ;i++){ if( numbers[i] %2 == 0){ ++even; }else{ ++odd; } } cout<<"\nThere are " <<even<<" even numbers in the give array"; cout<<"\nThere are " <<odd<< " odd numbers in the give array"; return 0; }
There are 6 even numbers in the give array There are 4 odd numbers in the give array
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